5k^(2/7)(7k^(3/7)+4k^(6/7))=0

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Solution for 5k^(2/7)(7k^(3/7)+4k^(6/7))=0 equation: 


k in (-oo:+oo)

5*k^(2/7)*(4*k^(6/7)+7*k^(3/7)) = 0

4*k^(6/7)+7*k^(3/7) = 0

k^(3/7)*(4*k^(3/7)+7) = 0

4*k^(3/7) = -7 // : 4

k^(3/7) = -7/4

( -7/4 < 0 i 3/7 in (0:1) ) => k naleu017Cy do O

k^(3/7) = 0

5*k^(2/7)*k^(3/7) = 0

( 5*k^(2/7) )

5*k^(2/7) = 0 // : 5

k^(2/7) = 0

k = 0

( k^(3/7) )

1*k^(3/7) = 0 // : 1

k^(3/7) = 0

k = 0

k in { 0, 0 }

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